Base | Representation |
---|---|
bin | 10010111011000000001… |
… | …111100101010110100100 |
3 | 11121022022112002002221021 |
4 | 102323000033211112210 |
5 | 132301011142342040 |
6 | 2433204014100524 |
7 | 162641531552515 |
oct | 22730017452644 |
9 | 4538275062837 |
10 | 1300305434020 |
11 | 4615025782aa |
12 | 1900117aa744 |
13 | 95806478728 |
14 | 46d13d74a0c |
15 | 23c55b5924a |
hex | 12ec03e55a4 |
1300305434020 has 48 divisors (see below), whose sum is σ = 2759175417600. Its totient is φ = 514688615424.
The previous prime is 1300305433951. The next prime is 1300305434023. The reversal of 1300305434020 is 204345030031.
It is not an unprimeable number, because it can be changed into a prime (1300305434023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15219381 + ... + 15304579.
It is an arithmetic number, because the mean of its divisors is an integer number (57482821200).
Almost surely, 21300305434020 is an apocalyptic number.
1300305434020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300305434020 is an abundant number, since it is smaller than the sum of its proper divisors (1458869983580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300305434020 is a wasteful number, since it uses less digits than its factorization.
1300305434020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93172 (or 93170 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 25.
The spelling of 1300305434020 in words is "one trillion, three hundred billion, three hundred five million, four hundred thirty-four thousand, twenty".
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