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130031102003 = 1172471631159
BaseRepresentation
bin111100100011001110…
…1010010100000110011
3110102122002110101112212
41321012131102200303
54112300430231003
6135422505442335
712252202062515
oct1710635224063
9412562411485
10130031102003
1150167192570
122124b1a03ab
13c35347429a
146417683bb5
1535b0958dd8
hex1e46752833

130031102003 has 8 divisors (see below), whose sum is σ = 141871772160. Its totient is φ = 118193708680.

The previous prime is 130031101999. The next prime is 130031102023. The reversal of 130031102003 is 300201130031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130031102003 - 22 = 130031101999 is a prime.

It is a super-2 number, since 2×1300311020032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130031102023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 735863 + ... + 895296.

It is an arithmetic number, because the mean of its divisors is an integer number (17733971520).

Almost surely, 2130031102003 is an apocalyptic number.

130031102003 is a deficient number, since it is larger than the sum of its proper divisors (11840670157).

130031102003 is a wasteful number, since it uses less digits than its factorization.

130031102003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1638417.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 130031102003 its reverse (300201130031), we get a palindrome (430232232034).

The spelling of 130031102003 in words is "one hundred thirty billion, thirty-one million, one hundred two thousand, three".

Divisors: 1 11 7247 79717 1631159 17942749 11821009273 130031102003