Base | Representation |
---|---|
bin | 11101100100001100111010… |
… | …101110010011011001100010 |
3 | 122001101212001022222022121121 |
4 | 131210030322232103121202 |
5 | 114020412213221244020 |
6 | 1140315245533442454 |
7 | 36250303242211660 |
oct | 3544147256233142 |
9 | 561355038868547 |
10 | 130031120103010 |
11 | 38482985437225 |
12 | 12700a9b04042a |
13 | 5772b60a19219 |
14 | 241777b299c30 |
15 | 100761b6c9baa |
hex | 76433ab93662 |
130031120103010 has 128 divisors (see below), whose sum is σ = 277216654832640. Its totient is φ = 42967009612800.
The previous prime is 130031120102999. The next prime is 130031120103029. The reversal of 130031120103010 is 10301021130031.
It is a super-2 number, since 2×1300311201030102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7937915020 + ... + 7937931400.
It is an arithmetic number, because the mean of its divisors is an integer number (2165755115880).
Almost surely, 2130031120103010 is an apocalyptic number.
130031120103010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130031120103010 is an abundant number, since it is smaller than the sum of its proper divisors (147185534729630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130031120103010 is a wasteful number, since it uses less digits than its factorization.
130031120103010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23252.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 130031120103010 its reverse (10301021130031), we get a palindrome (140332141233041).
The spelling of 130031120103010 in words is "one hundred thirty trillion, thirty-one billion, one hundred twenty million, one hundred three thousand, ten".
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