130031133932835 has 12 divisors (see below), whose sum is σ = 225387298816992. Its totient is φ = 69349938097488.

The previous prime is 130031133932789. The next prime is 130031133932837. The reversal of 130031133932835 is 538239331130031.

130031133932835 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 31 + 1 + 339 + 3 + 283 + 5 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-130031133932835 is a prime.

It is a super-2 number, since 2×130031133932835² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45), and also a Moran number because the ratio is a prime number: 2889580754063 = 130031133932835 / (1 + 3 + 0 + 0 + 3 + 1 + 1 + 3 + 3 + 9 + 3 + 2 + 8 + 3 + 5).

It is not an unprimeable number, because it can be changed into a prime (130031133932837) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1444790376987 + ... + 1444790377076.

It is an arithmetic number, because the mean of its divisors is an integer number (18782274901416).

Almost surely, 2^{130031133932835} is an apocalyptic number.

130031133932835 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130031133932835 is a deficient number, since it is larger than the sum of its proper divisors (95356164884157).

130031133932835 is a wasteful number, since it uses less digits than its factorization.

130031133932835 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2889580754074 (or 2889580754071 counting only the distinct ones).

The product of its (nonzero) digits is 524880, while the sum is 45.

The spelling of 130031133932835 in words is "one hundred thirty trillion, thirty-one billion, one hundred thirty-three million, nine hundred thirty-two thousand, eight hundred thirty-five".