Base | Representation |
---|---|
bin | 111100100011001110… |
… | …1101101101010100111 |
3 | 110102122002200001010010 |
4 | 1321012131231222213 |
5 | 4112300442310343 |
6 | 135422512101303 |
7 | 12252203035002 |
oct | 1710635555247 |
9 | 412562601103 |
10 | 130031213223 |
11 | 5016725908a |
12 | 2124b234833 |
13 | c3534b2ab2 |
14 | 64176b2539 |
15 | 35b097bd33 |
hex | 1e4676daa7 |
130031213223 has 4 divisors (see below), whose sum is σ = 173374950968. Its totient is φ = 86687475480.
The previous prime is 130031213203. The next prime is 130031213293. The reversal of 130031213223 is 322312130031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130031213223 - 212 = 130031209127 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 130031213223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130031213203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21671868868 + ... + 21671868873.
It is an arithmetic number, because the mean of its divisors is an integer number (43343737742).
Almost surely, 2130031213223 is an apocalyptic number.
130031213223 is a deficient number, since it is larger than the sum of its proper divisors (43343737745).
130031213223 is an equidigital number, since it uses as much as digits as its factorization.
130031213223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43343737744.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130031213223 its reverse (322312130031), we get a palindrome (452343343254).
The spelling of 130031213223 in words is "one hundred thirty billion, thirty-one million, two hundred thirteen thousand, two hundred twenty-three".
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