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130031254471 is a prime number
BaseRepresentation
bin111100100011001110…
…1110111101111000111
3110102122002202010200211
41321012131313233013
54112301000120341
6135422513020251
712252203266156
oct1710635675707
9412562663624
10130031254471
1150167287078
122124b254687
13c3534c87c1
1464176c359d
1535b0989181
hex1e46777bc7

130031254471 has 2 divisors, whose sum is σ = 130031254472. Its totient is φ = 130031254470.

The previous prime is 130031254421. The next prime is 130031254487. The reversal of 130031254471 is 174452130031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130031254471 - 211 = 130031252423 is a prime.

It is a super-3 number, since 3×1300312544713 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130031254421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65015627235 + 65015627236.

It is an arithmetic number, because the mean of its divisors is an integer number (65015627236).

Almost surely, 2130031254471 is an apocalyptic number.

130031254471 is a deficient number, since it is larger than the sum of its proper divisors (1).

130031254471 is an equidigital number, since it uses as much as digits as its factorization.

130031254471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 130031254471 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-four thousand, four hundred seventy-one".