Base | Representation |
---|---|
bin | 111100100011001111… |
… | …0010101100000110111 |
3 | 110102122002222100000011 |
4 | 1321012132111200313 |
5 | 4112301013021224 |
6 | 135422515401051 |
7 | 12252204314566 |
oct | 1710636254067 |
9 | 412562870004 |
10 | 130031376439 |
11 | 5016735a778 |
12 | 2124b2b3187 |
13 | c35353c183 |
14 | 6417715bdd |
15 | 35b09b0394 |
hex | 1e46795837 |
130031376439 has 2 divisors, whose sum is σ = 130031376440. Its totient is φ = 130031376438.
The previous prime is 130031376383. The next prime is 130031376473. The reversal of 130031376439 is 934673130031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130031376439 - 27 = 130031376311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130031376539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65015688219 + 65015688220.
It is an arithmetic number, because the mean of its divisors is an integer number (65015688220).
Almost surely, 2130031376439 is an apocalyptic number.
130031376439 is a deficient number, since it is larger than the sum of its proper divisors (1).
130031376439 is an equidigital number, since it uses as much as digits as its factorization.
130031376439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 40.
The spelling of 130031376439 in words is "one hundred thirty billion, thirty-one million, three hundred seventy-six thousand, four hundred thirty-nine".
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