Base | Representation |
---|---|
bin | 1011110100111000011110… |
… | …1000011100001000010010 |
3 | 1201001002101021211210110021 |
4 | 2331032013220130020102 |
5 | 3201020413212431010 |
6 | 43353321042254054 |
7 | 2511305653226353 |
oct | 275160750341022 |
9 | 51032337753407 |
10 | 13003141530130 |
11 | 4163668447894 |
12 | 156011995732a |
13 | 73426379459b |
14 | 32d4d934dd2a |
15 | 1783953858da |
hex | bd387a1c212 |
13003141530130 has 8 divisors (see below), whose sum is σ = 23405654754252. Its totient is φ = 5201256612048.
The previous prime is 13003141530083. The next prime is 13003141530143. The reversal of 13003141530130 is 3103514130031.
It can be written as a sum of positive squares in 2 ways, for example, as 10798893551889 + 2204247978241 = 3286167^2 + 1484671^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13003141530095 and 13003141530104.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650157076497 + ... + 650157076516.
Almost surely, 213003141530130 is an apocalyptic number.
13003141530130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13003141530130 is a deficient number, since it is larger than the sum of its proper divisors (10402513224122).
13003141530130 is a wasteful number, since it uses less digits than its factorization.
13003141530130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1300314153020.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 13003141530130 its reverse (3103514130031), we get a palindrome (16106655660161).
The spelling of 13003141530130 in words is "thirteen trillion, three billion, one hundred forty-one million, five hundred thirty thousand, one hundred thirty".
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