Search a number
-
+
13003144169 is a prime number
BaseRepresentation
bin11000001110000110…
…00011101111101001
31020120012201011110012
430013003003233221
5203112301103134
65550142301305
7640141621211
oct140703035751
936505634405
1013003144169
115572a32744
12262a887835
1312c2c32b62
148b4d47241
155118736ce
hex3070c3be9

13003144169 has 2 divisors, whose sum is σ = 13003144170. Its totient is φ = 13003144168.

The previous prime is 13003144111. The next prime is 13003144261. The reversal of 13003144169 is 96144130031.

13003144169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12232360000 + 770784169 = 110600^2 + 27763^2 .

It is an emirp because it is prime and its reverse (96144130031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13003144169 - 28 = 13003143913 is a prime.

It is a super-2 number, since 2×130031441692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13003144109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501572084 + 6501572085.

It is an arithmetic number, because the mean of its divisors is an integer number (6501572085).

Almost surely, 213003144169 is an apocalyptic number.

It is an amenable number.

13003144169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13003144169 is an equidigital number, since it uses as much as digits as its factorization.

13003144169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 13003144169 in words is "thirteen billion, three million, one hundred forty-four thousand, one hundred sixty-nine".