Base | Representation |
---|---|
bin | 111100100011001111… |
… | …0100111110100010100 |
3 | 110102122010010010211221 |
4 | 1321012132213310110 |
5 | 4112301022421122 |
6 | 135422521140124 |
7 | 12252205046302 |
oct | 1710636476424 |
9 | 412563103757 |
10 | 130031451412 |
11 | 50167401035 |
12 | 2124b32a644 |
13 | c353567335 |
14 | 6417735272 |
15 | 35b09c76c7 |
hex | 1e467a7d14 |
130031451412 has 6 divisors (see below), whose sum is σ = 227555039978. Its totient is φ = 65015725704.
The previous prime is 130031451397. The next prime is 130031451427. The reversal of 130031451412 is 214154130031.
It is an interprime number because it is at equal distance from previous prime (130031451397) and next prime (130031451427).
It can be written as a sum of positive squares in only one way, i.e., 82905988356 + 47125463056 = 287934^2 + 217084^2 .
It is a super-2 number, since 2×1300314514122 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16253931423 + ... + 16253931430.
Almost surely, 2130031451412 is an apocalyptic number.
It is an amenable number.
130031451412 is a deficient number, since it is larger than the sum of its proper divisors (97523588566).
130031451412 is a wasteful number, since it uses less digits than its factorization.
130031451412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32507862857 (or 32507862855 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 130031451412 its reverse (214154130031), we get a palindrome (344185581443).
The spelling of 130031451412 in words is "one hundred thirty billion, thirty-one million, four hundred fifty-one thousand, four hundred twelve".
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