Base | Representation |
---|---|
bin | 11101100100001101101111… |
… | …010110011001110001110101 |
3 | 122001101221022212100122221011 |
4 | 131210031233112121301311 |
5 | 114020421020233431013 |
6 | 1140315513313552221 |
7 | 36250334153032351 |
oct | 3544155726316165 |
9 | 561357285318834 |
10 | 130032003030133 |
11 | 38483298868466 |
12 | 127010a6875671 |
13 | 5772c719158c9 |
14 | 2417822650461 |
15 | 100766de82c3d |
hex | 76436f599c75 |
130032003030133 has 2 divisors, whose sum is σ = 130032003030134. Its totient is φ = 130032003030132.
The previous prime is 130032003030077. The next prime is 130032003030169. The reversal of 130032003030133 is 331030300230031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72718972561764 + 57313030468369 = 8527542^2 + 7570537^2 .
It is a cyclic number.
It is not a de Polignac number, because 130032003030133 - 213 = 130032003021941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130032001030133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016001515066 + 65016001515067.
It is an arithmetic number, because the mean of its divisors is an integer number (65016001515067).
Almost surely, 2130032003030133 is an apocalyptic number.
It is an amenable number.
130032003030133 is a deficient number, since it is larger than the sum of its proper divisors (1).
130032003030133 is an equidigital number, since it uses as much as digits as its factorization.
130032003030133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 130032003030133 its reverse (331030300230031), we get a palindrome (461062303260164).
The spelling of 130032003030133 in words is "one hundred thirty trillion, thirty-two billion, three million, thirty thousand, one hundred thirty-three".
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