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13003201123 = 111182109193
BaseRepresentation
bin11000001110000110…
…10001101001100011
31020120012211001120121
430013003101221203
5203112304413443
65550143421111
7640142246233
oct140703215143
936505731517
1013003201123
115572a71510
12262a8b4797
1312c2c52a63
148b4d5dcc3
155118854ed
hex3070d1a63

13003201123 has 4 divisors (see below), whose sum is σ = 14185310328. Its totient is φ = 11821091920.

The previous prime is 13003201121. The next prime is 13003201129. The reversal of 13003201123 is 32110230031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13003201123 - 21 = 13003201121 is a prime.

It is a super-2 number, since 2×130032011232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13003201097 and 13003201106.

It is not an unprimeable number, because it can be changed into a prime (13003201121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591054586 + ... + 591054607.

It is an arithmetic number, because the mean of its divisors is an integer number (3546327582).

Almost surely, 213003201123 is an apocalyptic number.

13003201123 is a deficient number, since it is larger than the sum of its proper divisors (1182109205).

13003201123 is a wasteful number, since it uses less digits than its factorization.

13003201123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1182109204.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13003201123 its reverse (32110230031), we get a palindrome (45113431154).

The spelling of 13003201123 in words is "thirteen billion, three million, two hundred one thousand, one hundred twenty-three".

Divisors: 1 11 1182109193 13003201123