Base | Representation |
---|---|
bin | 11101100100001101110001… |
… | …000001100100011100010011 |
3 | 122001101221101211012221101211 |
4 | 131210031301001210130103 |
5 | 114020421044431420334 |
6 | 1140315520200040551 |
7 | 36250334643566401 |
oct | 3544156101443423 |
9 | 561357354187354 |
10 | 130032031123219 |
11 | 38483302706195 |
12 | 127010b4163157 |
13 | 5772c776a0934 |
14 | 2417826284471 |
15 | 1007671681a64 |
hex | 764371064713 |
130032031123219 has 4 divisors (see below), whose sum is σ = 130039566171544. Its totient is φ = 130024496074896.
The previous prime is 130032031123213. The next prime is 130032031123237. The reversal of 130032031123219 is 912321130230031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130032031123219 - 25 = 130032031123187 is a prime.
It is a super-2 number, since 2×1300320311232192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130032031123213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3767498277 + ... + 3767532790.
It is an arithmetic number, because the mean of its divisors is an integer number (32509891542886).
Almost surely, 2130032031123219 is an apocalyptic number.
130032031123219 is a deficient number, since it is larger than the sum of its proper divisors (7535048325).
130032031123219 is an equidigital number, since it uses as much as digits as its factorization.
130032031123219 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7535048324.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 130032031123219 in words is "one hundred thirty trillion, thirty-two billion, thirty-one million, one hundred twenty-three thousand, two hundred nineteen".
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