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130032055325551 = 947913717908569
BaseRepresentation
bin11101100100001101110010…
…011101111001001101101111
3122001101221110111202112202111
4131210031302131321031233
5114020421122130404201
61140315522422504451
736250335356400211
oct3544156235711557
9561357414675674
10130032055325551
1138483315336815
1212701100295127
135772c7c6c5a42
1424178295845b1
151007673862b51
hex76437277936f

130032055325551 has 4 divisors (see below), whose sum is σ = 130045773243600. Its totient is φ = 130018337407504.

The previous prime is 130032055325539. The next prime is 130032055325581. The reversal of 130032055325551 is 155523550230031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032055325551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130032055325581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6858944806 + ... + 6858963763.

It is an arithmetic number, because the mean of its divisors is an integer number (32511443310900).

Almost surely, 2130032055325551 is an apocalyptic number.

130032055325551 is a deficient number, since it is larger than the sum of its proper divisors (13717918049).

130032055325551 is an equidigital number, since it uses as much as digits as its factorization.

130032055325551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13717918048.

The product of its (nonzero) digits is 337500, while the sum is 40.

The spelling of 130032055325551 in words is "one hundred thirty trillion, thirty-two billion, fifty-five million, three hundred twenty-five thousand, five hundred fifty-one".

Divisors: 1 9479 13717908569 130032055325551