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130032100331239 is a prime number
BaseRepresentation
bin11101100100001101110101…
…001001100100111011100111
3122001101221120122110001221211
4131210031311021210323213
5114020421220141044424
61140315531111252251
736250336444054141
oct3544156511447347
9561357518401854
10130032100331239
11384833387861a7
121270111337a087
135772c88b22b22
14241783153bc91
1510076777a2b94
hex764375264ee7

130032100331239 has 2 divisors, whose sum is σ = 130032100331240. Its totient is φ = 130032100331238.

The previous prime is 130032100331201. The next prime is 130032100331257. The reversal of 130032100331239 is 932133001230031.

It is a strong prime.

It is an emirp because it is prime and its reverse (932133001230031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032100331239 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130032100331239.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130032100301239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016050165619 + 65016050165620.

It is an arithmetic number, because the mean of its divisors is an integer number (65016050165620).

Almost surely, 2130032100331239 is an apocalyptic number.

130032100331239 is a deficient number, since it is larger than the sum of its proper divisors (1).

130032100331239 is an equidigital number, since it uses as much as digits as its factorization.

130032100331239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 31.

The spelling of 130032100331239 in words is "one hundred thirty trillion, thirty-two billion, one hundred million, three hundred thirty-one thousand, two hundred thirty-nine".