Base | Representation |
---|---|
bin | 11101100100001101110101… |
… | …001001100100111011100111 |
3 | 122001101221120122110001221211 |
4 | 131210031311021210323213 |
5 | 114020421220141044424 |
6 | 1140315531111252251 |
7 | 36250336444054141 |
oct | 3544156511447347 |
9 | 561357518401854 |
10 | 130032100331239 |
11 | 384833387861a7 |
12 | 1270111337a087 |
13 | 5772c88b22b22 |
14 | 241783153bc91 |
15 | 10076777a2b94 |
hex | 764375264ee7 |
130032100331239 has 2 divisors, whose sum is σ = 130032100331240. Its totient is φ = 130032100331238.
The previous prime is 130032100331201. The next prime is 130032100331257. The reversal of 130032100331239 is 932133001230031.
It is a strong prime.
It is an emirp because it is prime and its reverse (932133001230031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130032100331239 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130032100331239.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130032100301239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016050165619 + 65016050165620.
It is an arithmetic number, because the mean of its divisors is an integer number (65016050165620).
Almost surely, 2130032100331239 is an apocalyptic number.
130032100331239 is a deficient number, since it is larger than the sum of its proper divisors (1).
130032100331239 is an equidigital number, since it uses as much as digits as its factorization.
130032100331239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 130032100331239 in words is "one hundred thirty trillion, thirty-two billion, one hundred million, three hundred thirty-one thousand, two hundred thirty-nine".
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