Base | Representation |
---|---|
bin | 11101100100001101110101… |
… | …110110001011011001000111 |
3 | 122001101221121110110002012010 |
4 | 131210031311312023121013 |
5 | 114020421231134214421 |
6 | 1140315532210025303 |
7 | 36250336645331214 |
oct | 3544156566133107 |
9 | 561357543402163 |
10 | 130032112023111 |
11 | 38483344341501 |
12 | 12701117278233 |
13 | 5772c8b3877ac |
14 | 2417832d02b0b |
15 | 1007678812076 |
hex | 764375d8b647 |
130032112023111 has 4 divisors (see below), whose sum is σ = 173376149364152. Its totient is φ = 86688074682072.
The previous prime is 130032112023109. The next prime is 130032112023119. The reversal of 130032112023111 is 111320211230031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130032112023111 - 21 = 130032112023109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032112023119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21672018670516 + ... + 21672018670521.
It is an arithmetic number, because the mean of its divisors is an integer number (43344037341038).
Almost surely, 2130032112023111 is an apocalyptic number.
130032112023111 is a deficient number, since it is larger than the sum of its proper divisors (43344037341041).
130032112023111 is an equidigital number, since it uses as much as digits as its factorization.
130032112023111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43344037341040.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 130032112023111 its reverse (111320211230031), we get a palindrome (241352323253142).
The spelling of 130032112023111 in words is "one hundred thirty trillion, thirty-two billion, one hundred twelve million, twenty-three thousand, one hundred eleven".
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