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130032123221023 = 314194584620033
BaseRepresentation
bin11101100100001101110110…
…100000111001010000011111
3122001101221122020111222211121
4131210031312200321100133
5114020421242021033043
61140315533250031411
736250340142450202
oct3544156640712037
9561357566458747
10130032123221023
113848334a69a681
121270111ab78567
135772c907a868a
1424178345b9939
1510076797c4ded
hex76437683941f

130032123221023 has 4 divisors (see below), whose sum is σ = 134226707841088. Its totient is φ = 125837538600960.

The previous prime is 130032123221009. The next prime is 130032123221027. The reversal of 130032123221023 is 320122321230031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032123221023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130032123221027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2097292309986 + ... + 2097292310047.

It is an arithmetic number, because the mean of its divisors is an integer number (33556676960272).

Almost surely, 2130032123221023 is an apocalyptic number.

130032123221023 is a deficient number, since it is larger than the sum of its proper divisors (4194584620065).

130032123221023 is an equidigital number, since it uses as much as digits as its factorization.

130032123221023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4194584620064.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130032123221023 its reverse (320122321230031), we get a palindrome (450154444451054).

The spelling of 130032123221023 in words is "one hundred thirty trillion, thirty-two billion, one hundred twenty-three million, two hundred twenty-one thousand, twenty-three".

Divisors: 1 31 4194584620033 130032123221023