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13003230220259 is a prime number
BaseRepresentation
bin1011110100111000110011…
…1010110000111111100011
31201001002121110201201102212
42331032030322300333203
53201021103414022014
643353333531232335
72511311111125226
oct275161472607743
951032543651385
1013003230220259
114163703514014
1215601435a86ab
13734278c78256
1432d5070395bd
1517839d05423e
hexbd38ceb0fe3

13003230220259 has 2 divisors, whose sum is σ = 13003230220260. Its totient is φ = 13003230220258.

The previous prime is 13003230220181. The next prime is 13003230220261. The reversal of 13003230220259 is 95202203230031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13003230220259 - 28 = 13003230220003 is a prime.

It is a super-2 number, since 2×130032302202592 (a number of 27 digits) contains 22 as substring.

Together with 13003230220261, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13003230250259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501615110129 + 6501615110130.

It is an arithmetic number, because the mean of its divisors is an integer number (6501615110130).

Almost surely, 213003230220259 is an apocalyptic number.

13003230220259 is a deficient number, since it is larger than the sum of its proper divisors (1).

13003230220259 is an equidigital number, since it uses as much as digits as its factorization.

13003230220259 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 32.

The spelling of 13003230220259 in words is "thirteen trillion, three billion, two hundred thirty million, two hundred twenty thousand, two hundred fifty-nine".