Base | Representation |
---|---|
bin | 1011110100111000110011… |
… | …1010110000111111100011 |
3 | 1201001002121110201201102212 |
4 | 2331032030322300333203 |
5 | 3201021103414022014 |
6 | 43353333531232335 |
7 | 2511311111125226 |
oct | 275161472607743 |
9 | 51032543651385 |
10 | 13003230220259 |
11 | 4163703514014 |
12 | 15601435a86ab |
13 | 734278c78256 |
14 | 32d5070395bd |
15 | 17839d05423e |
hex | bd38ceb0fe3 |
13003230220259 has 2 divisors, whose sum is σ = 13003230220260. Its totient is φ = 13003230220258.
The previous prime is 13003230220181. The next prime is 13003230220261. The reversal of 13003230220259 is 95202203230031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13003230220259 - 28 = 13003230220003 is a prime.
It is a super-2 number, since 2×130032302202592 (a number of 27 digits) contains 22 as substring.
Together with 13003230220261, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13003230250259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501615110129 + 6501615110130.
It is an arithmetic number, because the mean of its divisors is an integer number (6501615110130).
Almost surely, 213003230220259 is an apocalyptic number.
13003230220259 is a deficient number, since it is larger than the sum of its proper divisors (1).
13003230220259 is an equidigital number, since it uses as much as digits as its factorization.
13003230220259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
The spelling of 13003230220259 in words is "thirteen trillion, three billion, two hundred thirty million, two hundred twenty thousand, two hundred fifty-nine".
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