13003300112232 has 16 divisors (see below), whose sum is σ = 32508250280640. Its totient is φ = 4334433370736.

The previous prime is 13003300112203. The next prime is 13003300112359. The reversal of 13003300112232 is 23221100330031.

It is a junction number, because it is equal to n+sod(n) for n = 13003300112199 and 13003300112208.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270902085648 + ... + 270902085695.

It is an arithmetic number, because the mean of its divisors is an integer number (2031765642540).

Almost surely, 2^{13003300112232} is an apocalyptic number.

13003300112232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13003300112232 is an abundant number, since it is smaller than the sum of its proper divisors (19504950168408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003300112232 is a wasteful number, since it uses less digits than its factorization.

13003300112232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 541804171352 (or 541804171348 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13003300112232 its reverse (23221100330031), we get a palindrome (36224400442263).

The spelling of 13003300112232 in words is "thirteen trillion, three billion, three hundred million, one hundred twelve thousand, two hundred thirty-two".