130033002222113 has 4 divisors (see below), whose sum is σ = 133057025529648. Its totient is φ = 127008978914580.

The previous prime is 130033002222091. The next prime is 130033002222119. The reversal of 130033002222113 is 311222200330031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130033002222113 - 2¹⁸ = 130033001959969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130033002222119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1512011653703 + ... + 1512011653788.

It is an arithmetic number, because the mean of its divisors is an integer number (33264256382412).

Almost surely, 2^{130033002222113} is an apocalyptic number.

It is an amenable number.

130033002222113 is a deficient number, since it is larger than the sum of its proper divisors (3024023307535).

130033002222113 is an equidigital number, since it uses as much as digits as its factorization.

130033002222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3024023307534.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130033002222113 its reverse (311222200330031), we get a palindrome (441255202552144).

The spelling of 130033002222113 in words is "one hundred thirty trillion, thirty-three billion, two million, two hundred twenty-two thousand, one hundred thirteen".