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1300330031113 = 10191276084427
BaseRepresentation
bin10010111011000001101…
…101011010100000001001
311121022101020100202210201
4102323001231122200021
5132301033441443423
62433210253212201
7162642250616251
oct22730155324011
94538336322721
101300330031113
11461515448483
12190019a91061
139580b5ab419
1446d17338961
1523c57db72ad
hex12ec1b5a809

1300330031113 has 4 divisors (see below), whose sum is σ = 1301606116560. Its totient is φ = 1299053945668.

The previous prime is 1300330031111. The next prime is 1300330031137. The reversal of 1300330031113 is 3111300330031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300330031113 - 21 = 1300330031111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300330031111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638041195 + ... + 638043232.

It is an arithmetic number, because the mean of its divisors is an integer number (325401529140).

Almost surely, 21300330031113 is an apocalyptic number.

It is an amenable number.

1300330031113 is a deficient number, since it is larger than the sum of its proper divisors (1276085447).

1300330031113 is a wasteful number, since it uses less digits than its factorization.

1300330031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1276085446.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 1300330031113 its reverse (3111300330031), we get a palindrome (4411630361144).

The spelling of 1300330031113 in words is "one trillion, three hundred billion, three hundred thirty million, thirty-one thousand, one hundred thirteen".

Divisors: 1 1019 1276084427 1300330031113