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1300332100121 is a prime number
BaseRepresentation
bin10010111011000001110…
…101010011101000011001
311121022101101020212221122
4102323001311103220121
5132301040004200441
62433210405415025
7162642304324325
oct22730165235031
94538341225848
101300332100121
114615166309aa
1219001a70a475
139580bb540a2
1446d17716985
1523c5817534b
hex12ec1d53a19

1300332100121 has 2 divisors, whose sum is σ = 1300332100122. Its totient is φ = 1300332100120.

The previous prime is 1300332100099. The next prime is 1300332100127. The reversal of 1300332100121 is 1210012330031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1291768633600 + 8563466521 = 1136560^2 + 92539^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300332100121 - 218 = 1300331837977 is a prime.

It is a super-3 number, since 3×13003321001213 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1300332100121.

It is not a weakly prime, because it can be changed into another prime (1300332100127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650166050060 + 650166050061.

It is an arithmetic number, because the mean of its divisors is an integer number (650166050061).

Almost surely, 21300332100121 is an apocalyptic number.

It is an amenable number.

1300332100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300332100121 is an equidigital number, since it uses as much as digits as its factorization.

1300332100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1300332100121 its reverse (1210012330031), we get a palindrome (2510344430152).

The spelling of 1300332100121 in words is "one trillion, three hundred billion, three hundred thirty-two million, one hundred thousand, one hundred twenty-one".