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130033213013339 is a prime number
BaseRepresentation
bin11101100100001110110111…
…011110000111110101011011
3122001102001110012011011211222
4131210032313132013311123
5114020431010012411324
61140320233340042255
736250406144520236
oct3544166736076533
9561361405134758
10130033213013339
1138483859872789
1212701383b3338b
1357731054c40bc
1424178d921c41d
1510076e02e155e
hex7643b7787d5b

130033213013339 has 2 divisors, whose sum is σ = 130033213013340. Its totient is φ = 130033213013338.

The previous prime is 130033213013299. The next prime is 130033213013371. The reversal of 130033213013339 is 933310312330031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130033213013339 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 130033213013299 and 130033213013308.

It is not a weakly prime, because it can be changed into another prime (130033213010339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016606506669 + 65016606506670.

It is an arithmetic number, because the mean of its divisors is an integer number (65016606506670).

Almost surely, 2130033213013339 is an apocalyptic number.

130033213013339 is a deficient number, since it is larger than the sum of its proper divisors (1).

130033213013339 is an equidigital number, since it uses as much as digits as its factorization.

130033213013339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39366, while the sum is 35.

The spelling of 130033213013339 in words is "one hundred thirty trillion, thirty-three billion, two hundred thirteen million, thirteen thousand, three hundred thirty-nine".