Base | Representation |
---|---|
bin | 11101100100001110110111… |
… | …011110000111110100110011 |
3 | 122001102001110012011011210111 |
4 | 131210032313132013310303 |
5 | 114020431010012411144 |
6 | 1140320233340042151 |
7 | 36250406144520151 |
oct | 3544166736076463 |
9 | 561361405134714 |
10 | 130033213013299 |
11 | 38483859872752 |
12 | 12701383b33357 |
13 | 57731054c408b |
14 | 24178d921c3d1 |
15 | 10076e02e1534 |
hex | 7643b7787d33 |
130033213013299 has 2 divisors, whose sum is σ = 130033213013300. Its totient is φ = 130033213013298.
The previous prime is 130033213013279. The next prime is 130033213013339. The reversal of 130033213013299 is 992310312330031.
It is an a-pointer prime, because the next prime (130033213013339) can be obtained adding 130033213013299 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130033213013299 - 25 = 130033213013267 is a prime.
It is not a weakly prime, because it can be changed into another prime (130033213013219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016606506649 + 65016606506650.
It is an arithmetic number, because the mean of its divisors is an integer number (65016606506650).
Almost surely, 2130033213013299 is an apocalyptic number.
130033213013299 is a deficient number, since it is larger than the sum of its proper divisors (1).
130033213013299 is an equidigital number, since it uses as much as digits as its factorization.
130033213013299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 40.
The spelling of 130033213013299 in words is "one hundred thirty trillion, thirty-three billion, two hundred thirteen million, thirteen thousand, two hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •