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1300333140103 = 61139153359257
BaseRepresentation
bin10010111011000001111…
…001010001100010000111
311121022101110012201112111
4102323001321101202013
5132301040240440403
62433210444001451
7162642316215334
oct22730171214207
94538343181474
101300333140103
11461517181298
1219001ab30287
139580c12956a
1446d1790798b
1523c582cd56d
hex12ec1e51887

1300333140103 has 8 divisors (see below), whose sum is σ = 1331158359440. Its totient is φ = 1269814639680.

The previous prime is 1300333140059. The next prime is 1300333140107. The reversal of 1300333140103 is 3010413330031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-1300333140103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300333140107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76671150 + ... + 76688107.

It is an arithmetic number, because the mean of its divisors is an integer number (166394794930).

Almost surely, 21300333140103 is an apocalyptic number.

1300333140103 is a deficient number, since it is larger than the sum of its proper divisors (30825219337).

1300333140103 is a wasteful number, since it uses less digits than its factorization.

1300333140103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153359457.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 1300333140103 its reverse (3010413330031), we get a palindrome (4310746470134).

The spelling of 1300333140103 in words is "one trillion, three hundred billion, three hundred thirty-three million, one hundred forty thousand, one hundred three".

Divisors: 1 61 139 8479 153359257 9354914677 21316936723 1300333140103