13003402320201 has 4 divisors (see below), whose sum is σ = 17337869760272. Its totient is φ = 8668934880132.

The previous prime is 13003402320199. The next prime is 13003402320247. The reversal of 13003402320201 is 10202320430031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13003402320201 - 2¹ = 13003402320199 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13003402120201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167233720031 + ... + 2167233720036.

It is an arithmetic number, because the mean of its divisors is an integer number (4334467440068).

Almost surely, 2^{13003402320201} is an apocalyptic number.

It is an amenable number.

13003402320201 is a deficient number, since it is larger than the sum of its proper divisors (4334467440071).

13003402320201 is an equidigital number, since it uses as much as digits as its factorization.

13003402320201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4334467440070.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 13003402320201 its reverse (10202320430031), we get a palindrome (23205722750232).

It can be divided in two parts, 13003 and 402320201, that added together give a palindrome (402333204).

The spelling of 13003402320201 in words is "thirteen trillion, three billion, four hundred two million, three hundred twenty thousand, two hundred one".