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130034086541353 = 467278445581459
BaseRepresentation
bin11101100100001111101011…
…100010010111100000101001
3122001102010201001212000000101
4131210033223202113200221
5114020434302123310403
61140320500142505401
736250436612423161
oct3544175342274051
9561363631760011
10130034086541353
1138484167964265
1212701588595261
13577321447c597
14241797d2475a1
151007741d3e71d
hex7643eb897829

130034086541353 has 4 divisors (see below), whose sum is σ = 130312532123280. Its totient is φ = 129755640959428.

The previous prime is 130034086541347. The next prime is 130034086541399. The reversal of 130034086541353 is 353145680430031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130034086541353 - 25 = 130034086541321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130034086541753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139222790263 + ... + 139222791196.

It is an arithmetic number, because the mean of its divisors is an integer number (32578133030820).

Almost surely, 2130034086541353 is an apocalyptic number.

It is an amenable number.

130034086541353 is a deficient number, since it is larger than the sum of its proper divisors (278445581927).

130034086541353 is an equidigital number, since it uses as much as digits as its factorization.

130034086541353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278445581926.

The product of its (nonzero) digits is 1555200, while the sum is 46.

The spelling of 130034086541353 in words is "one hundred thirty trillion, thirty-four billion, eighty-six million, five hundred forty-one thousand, three hundred fifty-three".

Divisors: 1 467 278445581459 130034086541353