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13003455041 is a prime number
BaseRepresentation
bin11000001110001000…
…01111101001000001
31020120020021221212222
430013010033221001
5203112341030131
65550153100425
7640144354433
oct140704175101
936506257788
1013003455041
115573125265
12262a9b7715
1312c30114c5
148b4dc8653
155118d587b
hex30710fa41

13003455041 has 2 divisors, whose sum is σ = 13003455042. Its totient is φ = 13003455040.

The previous prime is 13003455001. The next prime is 13003455043. The reversal of 13003455041 is 14055430031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8497152400 + 4506302641 = 92180^2 + 67129^2 .

It is a cyclic number.

It is not a de Polignac number, because 13003455041 - 26 = 13003454977 is a prime.

Together with 13003455043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13003455041.

It is not a weakly prime, because it can be changed into another prime (13003455043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501727520 + 6501727521.

It is an arithmetic number, because the mean of its divisors is an integer number (6501727521).

Almost surely, 213003455041 is an apocalyptic number.

It is an amenable number.

13003455041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13003455041 is an equidigital number, since it uses as much as digits as its factorization.

13003455041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 13003455041 its reverse (14055430031), we get a palindrome (27058885072).

The spelling of 13003455041 in words is "thirteen billion, three million, four hundred fifty-five thousand, forty-one".