13003540453 has 4 divisors (see below), whose sum is σ = 13004603788. Its totient is φ = 13002477120.

The previous prime is 13003540439. The next prime is 13003540471. The reversal of 13003540453 is 35404530031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9701659009 + 3301881444 = 98497^2 + 57462^2 .

It is a cyclic number.

It is not a de Polignac number, because 13003540453 - 2⁵ = 13003540421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003540493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513108 + ... + 537853.

It is an arithmetic number, because the mean of its divisors is an integer number (3251150947).

Almost surely, 2^13003540453 is an apocalyptic number.

It is an amenable number.

13003540453 is a deficient number, since it is larger than the sum of its proper divisors (1063335).

13003540453 is a wasteful number, since it uses less digits than its factorization.

13003540453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1063334.

The product of its (nonzero) digits is 10800, while the sum is 28.

The spelling of 13003540453 in words is "thirteen billion, three million, five hundred forty thousand, four hundred fifty-three".