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130039245035 = 5717218553353
BaseRepresentation
bin111100100011011110…
…0010110100011101011
3110102122122210002200122
41321012330112203223
54112310021320120
6135423400153455
712252331226240
oct1710674264353
9412578702618
10130039245035
1150170844547
1221251a6888b
13c35506584b
1464187a35c7
1535b1516a25
hex1e46f168eb

130039245035 has 16 divisors (see below), whose sum is σ = 188830097856. Its totient is φ = 83924487168.

The previous prime is 130039244989. The next prime is 130039245079. The reversal of 130039245035 is 530542930031.

It is a cyclic number.

It is not a de Polignac number, because 130039245035 - 222 = 130035050731 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130039244986 and 130039245004.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109276082 + ... + 109277271.

It is an arithmetic number, because the mean of its divisors is an integer number (11801881116).

Almost surely, 2130039245035 is an apocalyptic number.

130039245035 is a deficient number, since it is larger than the sum of its proper divisors (58790852821).

130039245035 is a wasteful number, since it uses less digits than its factorization.

130039245035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218553382.

The product of its (nonzero) digits is 48600, while the sum is 35.

The spelling of 130039245035 in words is "one hundred thirty billion, thirty-nine million, two hundred forty-five thousand, thirty-five".

Divisors: 1 5 7 17 35 85 119 595 218553353 1092766765 1529873471 3715407001 7649367355 18577035005 26007849007 130039245035