Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1011011100110111010 |
3 | 110102122201022002211221 |
4 | 1321012333123212322 |
5 | 4112310223132104 |
6 | 135423425342254 |
7 | 12252341130325 |
oct | 1710677334672 |
9 | 412581262757 |
10 | 130040052154 |
11 | 50171245991 |
12 | 2125219798a |
13 | c35528902c |
14 | 64189337bc |
15 | 35b1625c54 |
hex | 1e46fdb9ba |
130040052154 has 4 divisors (see below), whose sum is σ = 195060078234. Its totient is φ = 65020026076.
The previous prime is 130040052151. The next prime is 130040052209. The reversal of 130040052154 is 451250040031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 120670780129 + 9369272025 = 347377^2 + 96795^2 .
It is not an unprimeable number, because it can be changed into a prime (130040052151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32510013037 + ... + 32510013040.
Almost surely, 2130040052154 is an apocalyptic number.
130040052154 is a deficient number, since it is larger than the sum of its proper divisors (65020026080).
130040052154 is an equidigital number, since it uses as much as digits as its factorization.
130040052154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65020026079.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 130040052154 its reverse (451250040031), we get a palindrome (581290092185).
The spelling of 130040052154 in words is "one hundred thirty billion, forty million, fifty-two thousand, one hundred fifty-four".
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