13004011404442 has 4 divisors (see below), whose sum is σ = 19506017106666. Its totient is φ = 6502005702220.

The previous prime is 13004011404403. The next prime is 13004011404451. The reversal of 13004011404442 is 24440411040031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12428508617281 + 575502787161 = 3525409^2 + 758619^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13004011404442.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3251002851109 + ... + 3251002851112.

Almost surely, 2^{13004011404442} is an apocalyptic number.

13004011404442 is a deficient number, since it is larger than the sum of its proper divisors (6502005702224).

13004011404442 is an equidigital number, since it uses as much as digits as its factorization.

13004011404442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6502005702223.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 13004011404442 its reverse (24440411040031), we get a palindrome (37444422444473).

The spelling of 13004011404442 in words is "thirteen trillion, four billion, eleven million, four hundred four thousand, four hundred forty-two".