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130040142555 = 35120120633499
BaseRepresentation
bin111100100011011111…
…1110001101011011011
3110102122201110200212010
41321012333301223123
54112310234030210
6135423431321003
712252341655021
oct1710677615333
9412581420763
10130040142555
11501712a78a4
1221252220163
13c3552bb21b
146418958711
1535b1642920
hex1e46ff1adb

130040142555 has 32 divisors (see below), whose sum is σ = 208397952000. Its totient is φ = 69243609600.

The previous prime is 130040142511. The next prime is 130040142559. The reversal of 130040142555 is 555241040031.

It is not a de Polignac number, because 130040142555 - 214 = 130040126171 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130040142559) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37163196 + ... + 37166694.

It is an arithmetic number, because the mean of its divisors is an integer number (6512436000).

Almost surely, 2130040142555 is an apocalyptic number.

130040142555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130040142555 is a deficient number, since it is larger than the sum of its proper divisors (78357809445).

130040142555 is a wasteful number, since it uses less digits than its factorization.

130040142555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6771.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 130040142555 its reverse (555241040031), we get a palindrome (685281182586).

The spelling of 130040142555 in words is "one hundred thirty billion, forty million, one hundred forty-two thousand, five hundred fifty-five".

Divisors: 1 3 5 15 1201 2063 3499 3603 6005 6189 10315 10497 17495 18015 30945 52485 2477663 4202299 7218437 7432989 12388315 12606897 21011495 21655311 36092185 37164945 63034485 108276555 8669342837 26008028511 43346714185 130040142555