Base | Representation |
---|---|
bin | 111100100011011111… |
… | …1110001110010000011 |
3 | 110102122201110201102211 |
4 | 1321012333301302003 |
5 | 4112310234033404 |
6 | 135423431322551 |
7 | 12252341656165 |
oct | 1710677616203 |
9 | 412581421384 |
10 | 130040142979 |
11 | 501712a814a |
12 | 21252220457 |
13 | c3552bb486 |
14 | 6418958935 |
15 | 35b1642b04 |
hex | 1e46ff1c83 |
130040142979 has 2 divisors, whose sum is σ = 130040142980. Its totient is φ = 130040142978.
The previous prime is 130040142937. The next prime is 130040143021. The reversal of 130040142979 is 979241040031.
It is a balanced prime because it is at equal distance from previous prime (130040142937) and next prime (130040143021).
It is a cyclic number.
It is not a de Polignac number, because 130040142979 - 219 = 130039618691 is a prime.
It is not a weakly prime, because it can be changed into another prime (130040142079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65020071489 + 65020071490.
It is an arithmetic number, because the mean of its divisors is an integer number (65020071490).
Almost surely, 2130040142979 is an apocalyptic number.
130040142979 is a deficient number, since it is larger than the sum of its proper divisors (1).
130040142979 is an equidigital number, since it uses as much as digits as its factorization.
130040142979 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 130040142979 in words is "one hundred thirty billion, forty million, one hundred forty-two thousand, nine hundred seventy-nine".
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