1300402177142 has 16 divisors (see below), whose sum is σ = 1987676381952. Its totient is φ = 637936649280.

The previous prime is 1300402177099. The next prime is 1300402177147. The reversal of 1300402177142 is 2417712040031.

It is a junction number, because it is equal to n+sod(n) for n = 1300402177099 and 1300402177108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300402177147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23288513 + ... + 23344284.

It is an arithmetic number, because the mean of its divisors is an integer number (124229773872).

Almost surely, 2^{1300402177142} is an apocalyptic number.

1300402177142 is a deficient number, since it is larger than the sum of its proper divisors (687274204810).

1300402177142 is a wasteful number, since it uses less digits than its factorization.

1300402177142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46633063.

The product of its (nonzero) digits is 9408, while the sum is 32.

The spelling of 1300402177142 in words is "one trillion, three hundred billion, four hundred two million, one hundred seventy-seven thousand, one hundred forty-two".