Base | Representation |
---|---|
bin | 11000001110001100… |
… | …11010011011111001 |
3 | 1020120021100211201200 |
4 | 30013012122123321 |
5 | 203113012223140 |
6 | 5550213204413 |
7 | 640152243042 |
oct | 140706323371 |
9 | 36507324650 |
10 | 13004023545 |
11 | 55734833a7 |
12 | 262b030709 |
13 | 12c31801b6 |
14 | 8b50d58c9 |
15 | 511999030 |
hex | 30719a6f9 |
13004023545 has 24 divisors (see below), whose sum is σ = 23317561800. Its totient is φ = 6696324096.
The previous prime is 13004023517. The next prime is 13004023577. The reversal of 13004023545 is 54532040031.
13004023545 is a `hidden beast` number, since 1 + 300 + 4 + 0 + 2 + 354 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 3184006329 + 9820017216 = 56427^2 + 99096^2 .
It is not a de Polignac number, because 13004023545 - 26 = 13004023481 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4981080 + ... + 4983689.
It is an arithmetic number, because the mean of its divisors is an integer number (971565075).
Almost surely, 213004023545 is an apocalyptic number.
13004023545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13004023545 is a deficient number, since it is larger than the sum of its proper divisors (10313538255).
13004023545 is a wasteful number, since it uses less digits than its factorization.
13004023545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9964809 (or 9964806 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 27.
Adding to 13004023545 its reverse (54532040031), we get a palindrome (67536063576).
The spelling of 13004023545 in words is "thirteen billion, four million, twenty-three thousand, five hundred forty-five".
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