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13004030003 = 263142334747
BaseRepresentation
bin11000001110001100…
…11100000000110011
31020120021101011120212
430013012130000303
5203113012430003
65550213254335
7640152300626
oct140706340063
936507334525
1013004030003
115573488238
12262b0343ab
1312c3183113
148b50d7dbd
1551199add8
hex30719c033

13004030003 has 8 divisors (see below), whose sum is σ = 13063024128. Its totient is φ = 12945108744.

The previous prime is 13004029991. The next prime is 13004030059. The reversal of 13004030003 is 30003040031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004030003 - 28 = 13004029747 is a prime.

It is a Duffinian number.

It is a zygodrome in base 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13004030003.

It is not an unprimeable number, because it can be changed into a prime (13004030503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 356876 + ... + 391622.

It is an arithmetic number, because the mean of its divisors is an integer number (1632878016).

Almost surely, 213004030003 is an apocalyptic number.

13004030003 is a deficient number, since it is larger than the sum of its proper divisors (58994125).

13004030003 is a wasteful number, since it uses less digits than its factorization.

13004030003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36433.

The product of its (nonzero) digits is 108, while the sum is 14.

Adding to 13004030003 its reverse (30003040031), we get a palindrome (43007070034).

The spelling of 13004030003 in words is "thirteen billion, four million, thirty thousand, three".

Divisors: 1 263 1423 34747 374249 9138461 49444981 13004030003