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13004035423 = 193083221999
BaseRepresentation
bin11000001110001100…
…11101010101011111
31020120021101110000121
430013012131111133
5203113013113143
65550213335411
7640152322501
oct140706352537
936507343017
1013004035423
115573491315
12262b037567
1312c3185722
148b50d9d71
1551199c7ed
hex30719d55f

13004035423 has 8 divisors (see below), whose sum is σ = 13692960000. Its totient is φ = 12315561048.

The previous prime is 13004035417. The next prime is 13004035439. The reversal of 13004035423 is 32453040031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13004035423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004035453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52423 + ... + 169576.

It is an arithmetic number, because the mean of its divisors is an integer number (1711620000).

Almost surely, 213004035423 is an apocalyptic number.

13004035423 is a deficient number, since it is larger than the sum of its proper divisors (688924577).

13004035423 is a wasteful number, since it uses less digits than its factorization.

13004035423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 225101.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 13004035423 its reverse (32453040031), we get a palindrome (45457075454).

The spelling of 13004035423 in words is "thirteen billion, four million, thirty-five thousand, four hundred twenty-three".

Divisors: 1 19 3083 58577 221999 4217981 684422917 13004035423