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130040414331 = 361710603357
BaseRepresentation
bin111100100011100000…
…0110100000001111011
3110102122201222111122220
41321013000310001323
54112310321224311
6135423441215123
712252344166252
oct1710700640173
9412581874586
10130040414331
1150171473003
12212523314a3
13c355384b39
1464189c9799
1535b1698206
hex1e4703407b

130040414331 has 8 divisors (see below), whose sum is σ = 176229632784. Its totient is φ = 85272402720.

The previous prime is 130040414303. The next prime is 130040414333. The reversal of 130040414331 is 133414040031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130040414331 - 25 = 130040414299 is a prime.

It is a super-2 number, since 2×1300404143312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130040414333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355301496 + ... + 355301861.

It is an arithmetic number, because the mean of its divisors is an integer number (22028704098).

Almost surely, 2130040414331 is an apocalyptic number.

130040414331 is a deficient number, since it is larger than the sum of its proper divisors (46189218453).

130040414331 is an equidigital number, since it uses as much as digits as its factorization.

130040414331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 710603421.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 130040414331 its reverse (133414040031), we get a palindrome (263454454362).

The spelling of 130040414331 in words is "one hundred thirty billion, forty million, four hundred fourteen thousand, three hundred thirty-one".

Divisors: 1 3 61 183 710603357 2131810071 43346804777 130040414331