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13004063653 = 71857723379
BaseRepresentation
bin11000001110001101…
…00100001110100101
31020120021102212202011
430013012210032211
5203113020014103
65550214114221
7640152501010
oct140706441645
936507385664
1013004063653
115573500549
12262b04b971
1312c3195529
148b5106377
155119a5d6d
hex3071a43a5

13004063653 has 4 divisors (see below), whose sum is σ = 14861787040. Its totient is φ = 11146340268.

The previous prime is 13004063647. The next prime is 13004063659. The reversal of 13004063653 is 35636040031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13004063647) and next prime (13004063659).

It is not a de Polignac number, because 13004063653 - 221 = 13001966501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004063659) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 928861683 + ... + 928861696.

It is an arithmetic number, because the mean of its divisors is an integer number (3715446760).

Almost surely, 213004063653 is an apocalyptic number.

It is an amenable number.

13004063653 is a deficient number, since it is larger than the sum of its proper divisors (1857723387).

13004063653 is an equidigital number, since it uses as much as digits as its factorization.

13004063653 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1857723386.

The product of its (nonzero) digits is 19440, while the sum is 31.

The spelling of 13004063653 in words is "thirteen billion, four million, sixty-three thousand, six hundred fifty-three".

Divisors: 1 7 1857723379 13004063653