Base | Representation |
---|---|
bin | 11000001110001101… |
… | …10000110100100010 |
3 | 1020120021112111111120 |
4 | 30013012300310202 |
5 | 203113023141414 |
6 | 5550215153110 |
7 | 640153104255 |
oct | 140706606442 |
9 | 36507474446 |
10 | 13004115234 |
11 | 5573536280 |
12 | 262b075796 |
13 | 12c31b2b56 |
14 | 8b511b09c |
15 | 5119b62a9 |
hex | 3071b0d22 |
13004115234 has 32 divisors (see below), whose sum is σ = 28414622016. Its totient is φ = 3934806720.
The previous prime is 13004115217. The next prime is 13004115251. The reversal of 13004115234 is 43251140031.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13004115217) and next prime (13004115251).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 100837 + ... + 190200.
It is an arithmetic number, because the mean of its divisors is an integer number (887956938).
Almost surely, 213004115234 is an apocalyptic number.
13004115234 is an abundant number, since it is smaller than the sum of its proper divisors (15410506782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004115234 is a wasteful number, since it uses less digits than its factorization.
13004115234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 291730.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 13004115234 its reverse (43251140031), we get a palindrome (56255255265).
The spelling of 13004115234 in words is "thirteen billion, four million, one hundred fifteen thousand, two hundred thirty-four".
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