Search a number
-
+
1300412040211 = 9413138150647
BaseRepresentation
bin10010111011000110100…
…110010000010000010011
311121022120221200021010201
4102323012212100100103
5132301220440241321
62433222343040031
7162644264650654
oct22730646202023
94538527607121
101300412040211
11461557771099
12190041440017
139582259310b
1446d241a552b
1523c601b6291
hex12ec6990413

1300412040211 has 4 divisors (see below), whose sum is σ = 1300550200272. Its totient is φ = 1300273880152.

The previous prime is 1300412040203. The next prime is 1300412040281. The reversal of 1300412040211 is 1120402140031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300412040211 - 23 = 1300412040203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300412040281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69065911 + ... + 69084736.

It is an arithmetic number, because the mean of its divisors is an integer number (325137550068).

Almost surely, 21300412040211 is an apocalyptic number.

1300412040211 is a deficient number, since it is larger than the sum of its proper divisors (138160061).

1300412040211 is an equidigital number, since it uses as much as digits as its factorization.

1300412040211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138160060.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1300412040211 its reverse (1120402140031), we get a palindrome (2420814180242).

The spelling of 1300412040211 in words is "one trillion, three hundred billion, four hundred twelve million, forty thousand, two hundred eleven".

Divisors: 1 9413 138150647 1300412040211