Base | Representation |
---|---|
bin | 1011110100111100001010… |
… | …1110110000010100100010 |
3 | 1201001011221101112210021110 |
4 | 2331033002232300110202 |
5 | 3201024431024311232 |
6 | 43354003302004150 |
7 | 2511342353024034 |
oct | 275170256602442 |
9 | 51034841483243 |
10 | 13004133041442 |
11 | 41640270a2a24 |
12 | 1560355a16656 |
13 | 73439101ba7a |
14 | 32d590ccbc54 |
15 | 17840243bacc |
hex | bd3c2bb0522 |
13004133041442 has 8 divisors (see below), whose sum is σ = 26008266082896. Its totient is φ = 4334711013812.
The previous prime is 13004133041387. The next prime is 13004133041453. The reversal of 13004133041442 is 24414033140031.
It is a sphenic number, since it is the product of 3 distinct primes.
13004133041442 is an admirable number.
It is a super-2 number, since 2×130041330414422 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1083677753448 + ... + 1083677753459.
It is an arithmetic number, because the mean of its divisors is an integer number (3251033260362).
Almost surely, 213004133041442 is an apocalyptic number.
13004133041442 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004133041442 is a wasteful number, since it uses less digits than its factorization.
13004133041442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2167355506912.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 13004133041442 its reverse (24414033140031), we get a palindrome (37418166181473).
The spelling of 13004133041442 in words is "thirteen trillion, four billion, one hundred thirty-three million, forty-one thousand, four hundred forty-two".
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