Base | Representation |
---|---|
bin | 1011110100111100010000… |
… | …0100100011110010110001 |
3 | 1201001011222221212112222011 |
4 | 2331033010010203302301 |
5 | 3201030002304101023 |
6 | 43354005424042521 |
7 | 2511343045145353 |
oct | 275170404436261 |
9 | 51034887775864 |
10 | 13004155534513 |
11 | 4164038866340 |
12 | 1560361463441 |
13 | 734395895b90 |
14 | 32d593ca50d3 |
15 | 1784043d150d |
hex | bd3c4123cb1 |
13004155534513 has 16 divisors (see below), whose sum is σ = 15306820877376. Its totient is φ = 10891712658240.
The previous prime is 13004155534511. The next prime is 13004155534547. The reversal of 13004155534513 is 31543555140031.
It is a cyclic number.
It is not a de Polignac number, because 13004155534513 - 21 = 13004155534511 is a prime.
It is a super-2 number, since 2×130041555345132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13004155534511) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86864170 + ... + 87013747.
It is an arithmetic number, because the mean of its divisors is an integer number (956676304836).
Almost surely, 213004155534513 is an apocalyptic number.
13004155534513 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13004155534513 is a deficient number, since it is larger than the sum of its proper divisors (2302665342863).
13004155534513 is a wasteful number, since it uses less digits than its factorization.
13004155534513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173878464.
The product of its (nonzero) digits is 270000, while the sum is 40.
The spelling of 13004155534513 in words is "thirteen trillion, four billion, one hundred fifty-five million, five hundred thirty-four thousand, five hundred thirteen".
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