Base | Representation |
---|---|
bin | 111100100011100011… |
… | …0001110010100101111 |
3 | 110102122211122120100222 |
4 | 1321013012032110233 |
5 | 4112311202122001 |
6 | 135423531441555 |
7 | 12252362224505 |
oct | 1710706162457 |
9 | 412584576328 |
10 | 130041832751 |
11 | 50172251756 |
12 | 212528b62bb |
13 | c35576063c |
14 | 6418c78675 |
15 | 35b187861b |
hex | 1e4718e52f |
130041832751 has 2 divisors, whose sum is σ = 130041832752. Its totient is φ = 130041832750.
The previous prime is 130041832691. The next prime is 130041832757. The reversal of 130041832751 is 157238140031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130041832751 - 222 = 130037638447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130041832757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65020916375 + 65020916376.
It is an arithmetic number, because the mean of its divisors is an integer number (65020916376).
Almost surely, 2130041832751 is an apocalyptic number.
130041832751 is a deficient number, since it is larger than the sum of its proper divisors (1).
130041832751 is an equidigital number, since it uses as much as digits as its factorization.
130041832751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 130041832751 its reverse (157238140031), we get a palindrome (287279972782).
The spelling of 130041832751 in words is "one hundred thirty billion, forty-one million, eight hundred thirty-two thousand, seven hundred fifty-one".
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