130042404004301 has 4 divisors (see below), whose sum is σ = 130768897881600. Its totient is φ = 129315910127004.

The previous prime is 130042404004277. The next prime is 130042404004307. The reversal of 130042404004301 is 103400404240031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130042404004301 - 2²⁶ = 130042336895437 is a prime.

It is a super-2 number, since 2×130042404004301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130042404004307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363246938381 + ... + 363246938738.

It is an arithmetic number, because the mean of its divisors is an integer number (32692224470400).

Almost surely, 2^{130042404004301} is an apocalyptic number.

It is an amenable number.

130042404004301 is a deficient number, since it is larger than the sum of its proper divisors (726493877299).

130042404004301 is an equidigital number, since it uses as much as digits as its factorization.

130042404004301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 726493877298.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 130042404004301 its reverse (103400404240031), we get a palindrome (233442808244332).

The spelling of 130042404004301 in words is "one hundred thirty trillion, forty-two billion, four hundred four million, four thousand, three hundred one".