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13004255002 = 223832728547
BaseRepresentation
bin11000001110001110…
…10010111100011010
31020120021210121020011
430013013102330122
5203113042130002
65550222152134
7640154225614
oct140707227432
936507717204
1013004255002
115573621292
12262b12264a
1312c323165b
148b5155db4
155119e28d7
hex3071d2f1a

13004255002 has 8 divisors (see below), whose sum is σ = 19514575296. Its totient is φ = 6499396572.

The previous prime is 13004254999. The next prime is 13004255003. The reversal of 13004255002 is 20055240031.

13004255002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×130042550022 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13004255003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1359508 + ... + 1369039.

It is an arithmetic number, because the mean of its divisors is an integer number (2439321912).

Almost surely, 213004255002 is an apocalyptic number.

13004255002 is a deficient number, since it is larger than the sum of its proper divisors (6510320294).

13004255002 is a wasteful number, since it uses less digits than its factorization.

13004255002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2730932.

The product of its (nonzero) digits is 1200, while the sum is 22.

Adding to 13004255002 its reverse (20055240031), we get a palindrome (33059495033).

The spelling of 13004255002 in words is "thirteen billion, four million, two hundred fifty-five thousand, two".

Divisors: 1 2 2383 4766 2728547 5457094 6502127501 13004255002