Base | Representation |
---|---|
bin | 11000001110001110… |
… | …10011000001100011 |
3 | 1020120021210121200100 |
4 | 30013013103001203 |
5 | 203113042132311 |
6 | 5550222153443 |
7 | 640154226564 |
oct | 140707230143 |
9 | 36507717610 |
10 | 13004255331 |
11 | 5573621561 |
12 | 262b122883 |
13 | 12c3231852 |
14 | 8b515616b |
15 | 5119e2a56 |
hex | 3071d3063 |
13004255331 has 12 divisors (see below), whose sum is σ = 18795214152. Its totient is φ = 8664292896.
The previous prime is 13004255311. The next prime is 13004255347. The reversal of 13004255331 is 13355240031.
13004255331 is a `hidden beast` number, since 1 + 300 + 4 + 25 + 5 + 331 = 666.
It is not a de Polignac number, because 13004255331 - 26 = 13004255267 is a prime.
It is a super-2 number, since 2×130042553312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13004255295 and 13004255304.
It is not an unprimeable number, because it can be changed into a prime (13004255311) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 418386 + ... + 448391.
It is an arithmetic number, because the mean of its divisors is an integer number (1566267846).
Almost surely, 213004255331 is an apocalyptic number.
13004255331 is a deficient number, since it is larger than the sum of its proper divisors (5790958821).
13004255331 is a wasteful number, since it uses less digits than its factorization.
13004255331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 868450 (or 868447 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 13004255331 its reverse (13355240031), we get a palindrome (26359495362).
The spelling of 13004255331 in words is "thirteen billion, four million, two hundred fifty-five thousand, three hundred thirty-one".
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