Base | Representation |
---|---|
bin | 11000001110001110… |
… | …10011000001001111 |
3 | 1020120021210121122121 |
4 | 30013013103001033 |
5 | 203113042132221 |
6 | 5550222153411 |
7 | 640154226535 |
oct | 140707230117 |
9 | 36507717577 |
10 | 13004255311 |
11 | 5573621543 |
12 | 262b122867 |
13 | 12c3231838 |
14 | 8b5156155 |
15 | 5119e2a41 |
hex | 3071d304f |
13004255311 has 2 divisors, whose sum is σ = 13004255312. Its totient is φ = 13004255310.
The previous prime is 13004255287. The next prime is 13004255347. The reversal of 13004255311 is 11355240031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (11355240031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13004255311 - 27 = 13004255183 is a prime.
It is a super-2 number, since 2×130042553112 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004255711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502127655 + 6502127656.
It is an arithmetic number, because the mean of its divisors is an integer number (6502127656).
Almost surely, 213004255311 is an apocalyptic number.
13004255311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004255311 is an equidigital number, since it uses as much as digits as its factorization.
13004255311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 13004255311 its reverse (11355240031), we get a palindrome (24359495342).
The spelling of 13004255311 in words is "thirteen billion, four million, two hundred fifty-five thousand, three hundred eleven".
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