13004255387 has 2 divisors, whose sum is σ = 13004255388. Its totient is φ = 13004255386.

The previous prime is 13004255347. The next prime is 13004255389. The reversal of 13004255387 is 78355240031.

It is a strong prime.

It is an emirp because it is prime and its reverse (78355240031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13004255387 - 2²² = 13000061083 is a prime.

It is a super-2 number, since 2×13004255387² (a number of 21 digits) contains 22 as substring.

Together with 13004255389, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13004255387.

It is not a weakly prime, because it can be changed into another prime (13004255389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502127693 + 6502127694.

It is an arithmetic number, because the mean of its divisors is an integer number (6502127694).

Almost surely, 2^13004255387 is an apocalyptic number.

13004255387 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004255387 is an equidigital number, since it uses as much as digits as its factorization.

13004255387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 13004255387 in words is "thirteen billion, four million, two hundred fifty-five thousand, three hundred eighty-seven".